Calculate moles of:
3.0*(10)18 molecules of NH3
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1mole of nh3=6.023×10^23 molecules
x =3×10^18 molecules
by cross multiplication
x(6.023×10^23)=3×10^18
x=3×10^18/6.023×10^23
x=0.5×10^-5
x =3×10^18 molecules
by cross multiplication
x(6.023×10^23)=3×10^18
x=3×10^18/6.023×10^23
x=0.5×10^-5
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