Question

calculate moles of co2 produced when 3.8 litre butane burn​

Answer 1

58.0 g butane

in oxygen will produce  

3.99 mol carbon dioxide

.

Explanation:

Always start with a balanced equation.

2C 4 H 10  + 13O 2 → 8CO 2  + 10H 2 O

Determine the molar mass of butane.

Molar Mass of  C 4 H 10 : ( 4 × 12.011 g/mol ) + ( 10 × 1.008 g/mol ) =

58.124 g/mol

Determine the Mole Ratios for Butane and Carbon dioxide

2 mol C 4 H 10 8 mol CO 2  and  8 mol CO 22 mol C 4 H 10

Divide the given mass of butane by its molar mass (multiply by its reciprocal). This will give the moles of butane. Multiply times the molar ratio that places carbon dioxide in the numerator. This will give the moles of carbon dioxide.

58.0

g C 4 H 10 × 1 mol C 4 H 10 58.124 g C 4 H10 × 8 mol CO 2 2 mol C 4 H 10

=

3.99 mol CO

2

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Answer 2

Answer:

0.67 moles of CO2

Butane---C4H10

Explanation:

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