Question

calculate moles of o atoms in 9.00g of Mg (NO3)2​

Answer 1

Explanation:relative molecular  mass og Mg(NO3)2=24+2(14+48)=124+124=248

248g of Mg(NO3)2 contain 6 atom of O

then 9g will contain 6*9/248=54/248=0.21 atom of O

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