Question

Calculate moment of inertia of is ring of
mass 500 g & radius 0.5m about an axis of
rotation coinciding with its
diameter & tangent perpendicular to its
plane.
​

Answer 1

Answer:

Moment of inertia of rind about an axis of rotation coinciding wit its diameter and tangent perpendicular to its plane

I=

2

3

mr

2

Given : m=500 gm=0.5 kg r=0.5 m

⟹ I=

2

3×0.5×0.5

2

=0.1875 kg m

2