calculate (n+1)value for 3d and 4s and write in ascending order
Answers
Answer-Orbitals are arranged with increasing energy on the basis of (n + l) rule.The higher the value of (n + l) for an orbital the higher is its energy. Similarly the lower the value of (n + l) for an orbital the lower is its energy.If two orbitals possess same (n + l) value, the orbital with lower (n + l) value will have the lower energy.Let us find the energies of different orbitals3s orbital:n =3 , l= 0(n + l) = (3 + 0) = 33p orbital:n =3 , l= 1(n + l) = (3 + 1) = 44s orbital:n =4 , l= 0(n + l) = (4+ 0) = 4Both 3p and 4s orbitals have same (n + l) value, but the n value of 3p orbital is lower than 4s orbital hence, it will have lower energy.3d orbital:n =3 , l= 2(n + l) = (3+ 2) = 5The order of increasing energies of orbitals is 3s< 3p< 4s< 3d3s<3p<4s<3d.Option A is correct.
Answer:
calculate (n+1)value for 3d and 4s and write in ascending