Calculate nf of S2O3-2 forming S4O6-2
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the oxidation state of sulfur changes from +2 to +2.5 for one sulfur atom, i.e. an increase of 0.5 for one sulfur atom. There are two sulfur atoms in the reactant, hence the total increase in oxidation state will be 0.5 x 2 = 1.
Thus the n factor for the reactant is 1.
Explanation:
For such reaction we calculate the n factor for the atoms which show change in their oxidation states. Here the oxidation state of sulfur is changing
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