Question

Calculate
No.atoms of
in 270 g of glucose​

Answer 1

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Given :

Mass of glucose = 270 gm

Atomic mass of glucose =180 gm

To find :

No.of atoms in 270 gm glucose

solution :

$\frac{given \: mass_{glucose}}{atomic \: mass_{glucose}} = n_{moles \: of \: glucose} \\ \\n_{moles \: of \: glucose} = \frac{270}{180} = 1.5 \: mol \\ \\ glucose \rightarrow \: c_{6}h_{12}o_6 \\ \\ moles \: of \: carbon = 1.5 \times 6 = 9 \: moles \\ \\ moles \: of \: hydrogen = 12 \times 1.5 = 18 \: moles\\ \\ moles \: of \: oxygen = 6 \times 1.5 = 9 \: moles \\ \\ number \: of \: atoms \: present \: in \: carbn = 9 \times 6.022 \times {10}^{23} = 5.42 \times {10}^{24} \\ \\ number \: of \: atoms \: present \: in \: hydogen = 18 \times 6.022 \times {10}^{23} = 10.8 \times {10}^{24} \\ \\ number \: of \: atoms \: present \: in \: oxygen = 9 \times 6.022 \times {10}^{23} = 5.42 \times {10}^{24} \\ \\ total \: number \: of \: atoms \: present \: in \: 270 \: g \: glucose \: = (5.42 + 10.8 + 5.42) \times {10}^{24} \\ \\ \underline{\boxed{\sf{total \: number \: of \: atoms \: present \: in \: 270 \: g \: glucose = 2.64 \times {10}^{25} }}}$