Question

calculate no of aluminium ion in 10gm aluminium chloride​

Answer 1

Answer:

How many atoms are in 10 grams of aluminium?

1 mole of aluminium = 27g = 6.023×10^23 no.of atoms

27g of aluminium contains 6.023×10^23 no.of atoms

Therefore,10g…………………….6.023×10^23×10/27

= 2.23×10^23 no.of atoms

Molar mass Al = 27 g/mol

Mol Al in 10 g = 10 g / 27 g/mol = 0.37 mol

1 mol Al = 6.022*10²³ atoms

0.37 mol Al = 0.37*6.022*10²³ = 2.23*10²³ atoms

Gram atomic mass of Aluminium is 27 g

It means there is abhogadro no atom exist in 27 g of Aluminium

Therefore, in 27 g of Al atom exists 6.022×10^23

So, in 1 g of Al there's 6.022×10^23/27 atom

Therefore, in 10 g of Al there will be 6.022×10^23×10/27 = 6.022×10^24/27 = 2.23×10^23 atoms (approx)

And that's your answer (2.23×10^23 atoms)

So, I think you understand that first you have to know the atomic mass of the molecule. And note that there's always abhogadro no (6.022×10^23) of atoms exist if you express the atomic mass in gram. As an example if any molecule have atomic mass 10, then 10 g of that sample molecule will contain 6.022×10^23 no atoms. And after that you can easily do the rest of the sum by applying the unitary method.

Answer 2

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