Calculate no. Of atom in 106g of Na2CO3
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molecular mass of Na2CO3 is 106g
so no of atoms equal to given mass divided by molecular mass
i.e..no of mole multiplied by avagadro number
here no of atoms is therefore equal to
so no of atoms equal to given mass divided by molecular mass
i.e..no of mole multiplied by avagadro number
here no of atoms is therefore equal to
Bhuvan5075:
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No of atoms = same in every thing
Avagadro'so number =6.023×10^23
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