Question

Calculate no.of atom of each type present in 10mole of Na2Co3????​

Answer 1

Answer:

6.022*10^24

Explanation:

1 mole of Na2CO3 have 6.022*10^23 atoms

10 mole

$= 6.022 \times 10 ^{23} \times 1 0 \\ = 6.022 \times 10 ^{24}$

Answer 2

Answer:

10×6×6×10^23

=36×10^24

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