Question

calculate no of atoms and molecule present in 88g of o2 gas at htp​

Answer 1

Given mass of o2=88g

Molar mass of oxygen = 2*16 = 32  grams

$\rule{200}{2}$

Number of moles is equal to :-

$moles=\dfrac{mass\:given}{molar\:mass}$

Thus,

Number of moles of O2 will be :-

$Moles=\dfrac{88}{32}\\ \\ \\moles=2.75\:Moles$

$\rule{200}{2}$

we know that :-

$1\:Mole=N_A\:molecules$

hence;

Molecules of O2 given will be :-

$=2.75*N_A$

where:-

$N_A=AVOGADRO'S\:NUMBER\\ \\ \\N_A=6.022*10^{23}$

$\rule{200}{2}$

1 molecule of O2 has 2 atoms

Thus ,

Total Number of atoms of O given will be :-

$=2.75*N_A*2\\ \\ \\=5.5N_A\:Atoms$

where:-

$N_A=6.022*10^{23}$

$\rule{200}{2}$