Question

Calculate no of atoms in 1g of helium

Answer 1

heya friend!!☺☺
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here's your answer!!☺☺⬇⬇

The molar mass that is the mass of 6.022 X 10^23 atoms of helium is 4g.

Hence 1 mole of He = 4 g of He = 6.022 X 10^23 atoms of He

1 g of He = (6.022 X 102^3) / 4 atoms of He
=1.5055 × 10^23 atoms...

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hope it helps you!!☺☺

Answer 2

The number of atoms in 1g of helium is 1.5 × 10²³ atoms.

Given:

1g of helium.

To Find:

The number of atoms in 1g of helium.

Solution:

To find the number of atoms in 1g of helium we will follow the following steps:

As we know,

1 mole of any substance contains an Avogadro number of atoms or 6.022 × 10²³ atoms.

So

Number of moles of helium in 1g of helium =

$\frac{given \: mass}{molecular \: mass} = \frac{1}{4} moles$

Now,

$Number \: of \: atoms \: present \: in \: 1g \: or \frac{1}{4} moles \: of \: helium \: = \frac{1}{4} \times 6.022 \times {10}^{23} = 1.5 \times {10}^{23} atoms$

Henceforth, the number of atoms in 1g of helium is 1.5 × 10²³ atoms.

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