Calculate no of atoms of C, H & O in 6.84mg of surcose
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Answer:
sucrose is (fructose + glucose) i.e. C6H12O6 + C6H12O6 so total no for atoms is 48 so
1mg = 10^-3 g
so
6.84 * 10^-3 g
C atoms = 12 * 6.84*10^-3 * 6.022*10^23/12
and this is how the rest are gonna be...
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