calculate no. of atoms of nitrogen in 5.6 GM of nitrogen
Answers
Mass of nitrogen = 5.6 g
Atomic mass of N = 14 u
Molar atomic mass of N = 14 g / mol ,
Molar mass of N2 = 2 x 14 g / mol = 28 g mol-1
(a) No. of moles of N2 in 5.6 g of nitrogen
= 5.6 g/28 g mol-1
= 0.2 mol
(b) No. of molecules of N2 is 5.6 g of nitrogen
= 6.023 x 10^23 x No. of moles of N2
= 6.023 x 10^23 x 0.2
= 1.2 x 10^23
© As one molecule of N2 contains two N atoms.
No. of atoms of nitrogen
= 2 x No. of N2 molecules
= 2 x 1.2 x 10^23 = 2.4 x 10^23
Answer:
Mass of nitrogen = 5.6 g
Atomic mass of N = 14 u
Molar atomic mass of N = 14 g / mol ,
Molar mass of N2 = 2 x 14 g / mol = 28 g mol-1
(a) No. of moles of N2 in 5.6 g of nitrogen
= 5.6 g/28 g mol-1
= 0.2 mol
(b) No. of molecules of N2 is 5.6 g of nitrogen
= 6.023 x 10^23 x No. of moles of N2
= 6.023 x 10^23 x 0.2
= 1.2 x 10^23
© As one molecule of N2 contains two N atoms.
No. of atoms of nitrogen
= 2 x No. of N2 molecules
= 2 x 1.2 x 10^23 = 2.4 x 10^23
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