Question

calculate no. of atoms present in 18g of glucose​

Answer 1

$Number .of. moles = \frac{given. mass}{molecular.mass}$

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Given mass of glucose = 18 g

Molar mass of glucose = 180 g

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No. of moles = 18/180 = 0.1 Mole.

Glucose ------ C6H12O6

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By mole concept,

In 1 mole of Glucose there are  24 x 6.022 x 10^23 Atoms.

So,

No. of atoms In 0.1 moles of glucose molecule ----

= 0.1 x 24 x 3 x 6.022 x 10^23

= 14.4528 x 10^23