Calculate no.of atoms present in 9gram of Aluminium
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Atomic weight of Al=27g
Given weight=9g
Number of moles=9/27=1/3moles
Number of atoms=1/3 × NA=3.01×10^23
Given weight=9g
Number of moles=9/27=1/3moles
Number of atoms=1/3 × NA=3.01×10^23
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