Question

calculate no of electrons moving in an element carrying 5MA of current in 10 seconds ​

Answer 1

Explanation:

Current (I) = 5 mA

Time (t) = 10 seconds

Current (I) = Charge (q) / time (t)

Charge (q) = Current (I) × time (t)

$q \: = 5 \times {10}^{ - 3}$

$q \: = 5 \times {10}^{ - 2}$

q = n e

$n \: = \frac{q}{e}$

$n \: = \frac{5 \times {10 }^{ - 2} }{1.6{10}^{ - 19} }$

$n \: = 3.125 \times {10}^{17}$