Question

calculate no. of electrons present in 2 ampere of current flows for 2 milli sec
please help me solving it ​

Answer 1

Answer:

23 electrons are present plz mark as a brainlist

Answer 2

Explanation:

given: I = 2 A

time = 2 milli sec = 2×10^-3 sec

we know I=Q/T

and also Q= ne

so.. I= ne/T

ne= I×T=2×2×10^-3=4×10^-3 ELECTRONS