Question

Calculate no. Of electrons present in 9.5 g of phosphate(PO4)

Answer 1

Explanation:

na molecules of po4 equals 95g

na/10molecules of po4 equals 9.5g

in 1 molecule there are 15plus 32equals 47 electrons

so in na /10molecules there are

47*na/10= 47*6.022*10^22 electrons

Answer 2

Answer:

5 Na bcz add those 3 electrons which is added in the compound may be