Question

calculate no. of electrons present in 9.5g of PO4³​

Answer 1

molar mass of (PO4)3-is 95 g

given mass is 9.5 g

number of moles=9.5/95= 0.1

1mole contain 6*10^23 components

(in this case ion)

0.1 moles contain 6*10^22 ions

but each ion has 50 electron (15+32+3)

Thus total electrons in 9.5 g of (PO4)3-is [6*10^22]* 50

=3*10^24 electron