Question

calculate no. of electrons, protons and neutron mg2+ and Na​

Answer 1

Answer:

20×6.02×10^23

24g Mg is 1 mol so 48g Mg is 2 mol Mg2+ has lost 2 electrons so has total now 10×NA for two mol it becomes 20×NA

Answer 2

Answer:

24 gm of Magnesium contains=N

A

atoms. Where N

A

= 6.023 × 10

23

48 gm of Mg contains =2N

A

atoms.

1 atom of Mg contains 12 electrons

Mg

2+

ion will contain (12–2)=10 electrons

2N

A

Mg

2+

ions will contain

=10×2N

A

electrons

=10×2×6.023×10

23

=20N

A

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