Question

calculate no. of hydrogen atoms in 60g of urea​

Answer 1

Answer:

361.32 × $10^{23}$ atom

Explanation:

mol of 60g of H = 60g /60 gmol-1

no of H atom in 60mol = 60 × 6.022  × $10^{23}$

                                      =361.32 × $10^{23}$ atom

Answer 2

Answer:

24 * 10 ^23  

Explanation:

molar mass of urea = 60 g

no of moles of urea = 60 /60 = 1 mol

formulae of urea -- CH4N2O

from the formulae it is clear that 1 mol of urea has 4 g of hydrogen

that is ,

1 mol of urea------- 4 g of H

1 g H contains avagadro no of atoms

therefore 4 g H --------- avagadro no  * 4 atoms

                        = 6.023 * 10^23 * 4       [avagadro no=6.023*10 ^ 23 ]

                       = 24.092 * 10^23

                     = 24 * 10^23  ( when we round off above value)

hope it help u