Question

calculate no of molecule present in 25 gram of calcium carbonate​

Answer 1

Answer:

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Answer 2

Answer:No. of moles = given mass of compound / Molar mass

Given mass = 25g

Molar mass = (40 + 12 + 3x16) =100g/mol

No of moles of CaCO3 = 25/ 100 =0.25mol

According to Avogadro’s law –

1 mol of CaCO3 molecules contains 6.022 x 10²³ CaCO3 molecules

Hence, 0.25mol of CaCO3 molecules will contain 6.022 10²³ x 0.25 molecules

= 0.6022 x 10²²molecules