calculate no of molecules and atoms in 5.60 L of ozone at n. t. p
yxvxkx25:
the Q is for chem.... not bio (typo)
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1 mole ozone contains Na molecules
22.4 l ozone contains Na molecules
5.6 l ozone contains Na*5.6/22.4 = Na/4 = 6.02*10^23 / 4 = 1.5*10^23 molecules
and
1 molecule of ozone contains 3 atoms of O
so,
no. of atoms = 3 * 1.5* 10^23 = 4.5*10^23 atoms
22.4 l ozone contains Na molecules
5.6 l ozone contains Na*5.6/22.4 = Na/4 = 6.02*10^23 / 4 = 1.5*10^23 molecules
and
1 molecule of ozone contains 3 atoms of O
so,
no. of atoms = 3 * 1.5* 10^23 = 4.5*10^23 atoms
done*
1 mole contains Na molecules
1 mole contains 22.4l volume
so, 22.4l contains Na molecules
i get it but it has nothing to do with this Q.....
we need to calculate no. of molecules in 5.6 l right?
so, if 22.4 l contains Na molecules then 5.6 l contains Na/4 molecules
but where is ozone
we are calculate no. of molecules of ozone only
but..... k... leave it... btw thx for helping
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