Question

Calculate no. of Moleculs present in 3.2
g of Marcs gas (CH4)



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Answer 1

Answer:

No of molecules =1.20*10^23

Explanation:

,as 1 mole of mars gas =6.022*10^23 molecules

And, 1 mole of mars gas =16g

So,16 g=6.022*10^23

1g=6.022*10^23/16

3.2g =6.022*10^23*3.2/16

=1.20*10^23