Question

calculate no. of moles and molecules present in 546 dm^3 of hcl

PLZ ANSWER MY QUESTION 2MORROW IS MY EXAAAMMMMM PLZZZZZZZZ

CALCULATE NO.OF MOLES AND MOLECULES PRESENT IN 300 MG OF METHANE

Answer 1

Hi mate.


Thanks for asking this question.


Here is your answer,



(1)


Given :

V = 546 dm3 = 546 L.


We know that,

$n \: = \frac{v}{22.4}$

$n \: = \frac{546}{22.4}$


$n = 24.37 \:$


For the,

Calculation of no. Of molecules,

We have,



$no. \: of \: molcule = n \times ava. \: no.$

$no. \: of \: molecule = 24.37 \times {6.022}^{23}$

$no. \: of \: molecule = 146.75 \times {10}^{23}$




(2)

Given :

W = 300mg = 0.3 g

Molar mass = C + H×4

= 12 + 1 × 4

= 16 g.

We know that.



$n = \frac{w}{m}$

$n = \frac{0.3}{16}$


$n \: = 18.7 \times {10}^{ - 3}$


For calculating.

No of molecules,




$no. \: of \: molecules = n \times ava. \: no.$

$no. \: of \: molecules = 18.7 \times {10}^{ - 3} \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6.022 \times {10}^{23}$


$no. \: of \: molecules = 112.61 \times {10}^{20}$


$no. \: of \: molecules = 1.12 \times {10}^{22}$







Thank you.




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