Question

Calculate no.of moles in 31.6g of kMno4

Answer 1

Answer:

Explanation:

no.of moles = given mass / gmm

gmm  of kmno4 = 39 +55+(4×16)

                             = 158 g

no.of moles = 31.6 /158

                      =0.2 moles

Answer 2

Given:

31.6 g of KMnO₄

To Find:

Number of moles of 31.6 g of KMnO₄

Solution:

We know that,

$\red{\bigstar \ \boxed{\sf n=\dfrac{M}{GMW}}}$

Here,

• n = Mole

• M = Given mass

• GMW = Gram Molecular Weight

According to the Question,

We are asked to find the number of moles of 31.6 g of KMnO₄

Given that,

31.6 g of KMnO₄

Hence,

• M = 31.6 g

We know that,

Molecular mass of KMnO₄ = 158.034 g/mol

Hence,

• GMW = 158.034 g/mol

By Substituting the values,

We get,

$\blue{\sf \implies n=\dfrac{31.6}{158.034} \ moles }$

$\green{\sf \implies n=0.1999 \ moles}$

$\pink{\sf \implies n \approx 0.20 \ moles}$

Therefore,

0.20 moles of KMnO₄ is present in 31.6 g of KMnO₄