Question

Calculate no. of moles in Ca3(PO4)2 that contains 0.04 moles of oxygen atom.
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Answer 1

Answer:

1 mole of Ca3(PO4)2 has 8 moles of oxygen, so for 0.25 mole of atomic oxygen you need (0.25/8 =) 0.03125 mole of the compound.

PLZZ MARK AS BRAINLIST

Answer 2

Answer:

8 moles of Oxygen = 1 mole of Ca3(PO4)2

1 mole of Oxygen = 1/8 mole of Ca3(PO4)2

then 0.04 mole of oxygen = 1/8 * 0.04

= 0.005 mole

this ans is totally correct....no defects in it