Question

Calculate no . Of moles of H2 present in 500cc flask at 300 k 760 mm pressure.if mass of this gas is 4.09×10-2 g find molecular mass​

Answer 1

Answer:

Solution: The data given in the problem is P = 760mm of Hg = 1 atm V = 500cm3 T = 270C T = 27+ 273 = 300 K R = 82.1 cm3 K-1mol-1 number of moles of hydrogen (n) = ? According to ideal gas equation PV= nRT n = PV/RT = 1 atm X 500 cm3 /82.1 cm3 K-1mol-1 X 300 K n = 0.0203mol