Calculate no. of moles of H2C2O4.2H2O (oxalic acid) in 6.3g of
oxalic acid.
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Explanation:
no. of moles= given no. of moles / molecular weight of compound
oxlaicacid=
H2C2O4.2H2O=2×2+2×12+4×16+2×2×2×16
= 128
no. of moles = 6.3/128
=0.0492...
=0.5 moles
no. of molecules= 6.022 ×10 raised to 23×0.5
= 3.011 × 10 raised to 23
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