Calculate no of moles of oxygen in 1mol of ethanol
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The stoichiometry of the reaction says that 1 molecule of ethanol will react with 3 molecules of oxygen gas, which also means 1 mol C2H5OH will react with 3 mol O2. Since 1 mole of oxygen atoms is 16.00 g, 2 mol O atoms is 32.00 g, and O2 has a molar mass of 32.00 g⁄mol. 3 mol O2 will be 32.00 g⁄mol × 3 mol = 96.00 g.
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Answer:
1 mol of ethanol. C2H5OH (ethanol) – Molar mass. = 24 + 6 + 16. = 46. 46 g of ethanol contains 1 × 6.023 × 1023 number of oxygen atoms.
1 mol of formic acid. HCOOH (formic acid) – Molar mass. = 2+12 + 32. = 46. 46 g of HCOOH contains 2 × 6.023 × 1023 number of oxygen atoms.
Explanation:
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