Calculate no. of moles of oxygen present in 22g of co2
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mass of co2 : 12 + 16*2 = 12+32 = 44u
given mass = 22g
no. of moles of co2 = given mass / molar mass = 22 / 44 = 0.5 moles
Now in CO2
1 C atom and 2 oxygen atoms
so 1 mole of CO2 has 1mole of carbon and 2 moles of oxygen
thus in 0.5 moles there are 2 / 2 = 1 mole of oxygen in 22g (0.5 moles) of CO2.
given mass = 22g
no. of moles of co2 = given mass / molar mass = 22 / 44 = 0.5 moles
Now in CO2
1 C atom and 2 oxygen atoms
so 1 mole of CO2 has 1mole of carbon and 2 moles of oxygen
thus in 0.5 moles there are 2 / 2 = 1 mole of oxygen in 22g (0.5 moles) of CO2.
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Answer:
Step-by-step explanation:
If there is half as a power with any no. Such as - 49½
Then it becomes √49
that is = 7.
Or suppose there is 64⅓
Then = ³√64
= 4
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