Question

calculate no of moles of water present in 488gm of Bacl2 2 h2o

Answer 1

Answer:

The molar mass (that is the mass of one mole) of BaCl2.2H2O is 244g. Each mole of this compound contains 2 moles of water. Thus

244 g of BaCl2.2H2O → 2 moles of water

1g of BaCl2.2H2O → (2 / 244) moles of water

488 g of BaCl2.2H2O → (2 X 488) / 244 moles of water

= 4 moles of water

So, 488g of BaCl2 contains 4 moles of water

Explanation:

Answer 2

Answer:

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