Question

calculate no. of nitride ions in 25g of Magnesium Nitride with steps

Answer 1

Answer:

Number of moles in nitrate ions of 25g of Mg(No3)2  = 0.336 moles.

Explanation:

given mass of Mg(No3)2 = 25 g

molar mass of Mg(No3)2 = 24 + 2(14) + 6(16)

       = 24 + 28 + 96

       = 148

 { 1 atom of Mg = 24,

   1 atom of nitrogen = 14

   2 atom of nitrogen = 2(14) = 28

   1 atom of oxygen = 16

   6 atom of oxygen = 6(16) = 96}

mole of Mg(No3)2 = given mass / molar mass

                               =  25 / 148

                               = 0.168

each Mg(No3)2 contains 2 nitrate ions

so,

moles of nitrate ions = 2 x moles of Mg(No3)2

                                   = 2 x 0.168

                                   = 0.336

therefore, number of moles in nitrate ions of 25g of Mg(No3)2  = 0.336 moles.