Question

calculate no of nitrogen atom in 160amu ​

Answer 1

NH4NO3 is made up by N,H and O.

2H2 +2 N2 +3O2 ——-> 2NH4NO3

So 160 amu = 160g

but,

    mole = mass/molar mass

     mole = 160g/80g/mol

     mole = 2mol

but,

    from reaction 2NH4NO3= 2*2, =4 mol

Therefore,

    2N2——-> 2NH4NO3

The mole ratio is 2:2, so the mole of Ammonium nitrate is equal of nitrogen gase  but

number of atom = no~ of mole * Avogadros contant

N = 4mol * 6.022*10^23

N = 2.4088*10^24

N =2.41*10^24 atom.

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