calculate no. of oxide ions present in 10g of calcium carbonate
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Molar mass of CaCO3 = 40 + 12 + 16 x 3 = 100
(A) Amount of carbon in 10 g of CaCO3 = 0.12 g = 1.2/12 g-atom = 0.1 g-atom.
(B) Amount of oxygen in 10 g of CaCO3 = 4.8 g = 4.8/16 g-atom = 0.3 g-atom.
(C) Amount of calcium in 10 g of CaCO3 = 4 g.
So the correct answer is (B) only.
(A) Amount of carbon in 10 g of CaCO3 = 0.12 g = 1.2/12 g-atom = 0.1 g-atom.
(B) Amount of oxygen in 10 g of CaCO3 = 4.8 g = 4.8/16 g-atom = 0.3 g-atom.
(C) Amount of calcium in 10 g of CaCO3 = 4 g.
So the correct answer is (B) only.
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