Question

calculate no of particles 88 gram of carbon dioxide molecules​

Answer 1

Answer:

no of moles= 88/44 =2

therefore no. of molecules =

6.023 \times {10}^{23} \times 26.023×1023×2

therefore no.of molecules= 12.046*10^23

Answer 2

Answer:

The number of molecules in 88g of CO_2CO

2

is equal to 24.088\times 10^2^3 .

Explanation:

The molar mass of CO_2CO

2

is given to be addition of the molar masses of one carbon atom and two oxygen atoms.

That is equal to 12 + 16 \times 212+16×2 which gives us 44g.

Therefore 44g is one mole of CO_2CO

2

which means that 88g will be two moles of CO_2CO

2

.

This also means that if one mole of CO_2CO

2

has two moles of O_2O

2

then two moles of CO_2CO

2

will have four moles of O_2O

2

.

Therefore in order to find out the "total number of atoms" of CO_2CO

2

, we have to multiply the total number of the moles present with the Avogadro number.

4 \times 6.023\times 10 ^ 2^3, this value gives us 24.088 \times10^2^3 which is the number of molecules in 88g of CO_2CO

2

.

4 moles of oxygen contains = 4\times 6.023\times10^2^3

= 24.092\times10^2^3

= 2.4092 X 10^2^4 atoms of oxygen.

Convert into mole 22 g of carbon dioxide.