Question

calculate no of particles present in 16g of solid shulphur

Answer 1

Heya user !!!

Here's the answer you are looking for

The molecular mass of Sulphur is 32 gram

So, 32 gram of sulphur is equal to 1 mole

and 16 gram of Sulphur is equal to 1/2 moles = 0.5 moles.

one mole contains in a NA number particles that is 6.023 × 10²³ particles.

So, 0.5 moles of Sulphur will contain

6.023 × 10²³ × 0.5 particles or atoms

= 3.011 × 10²³ particles.

Therefore, the number of particles present in 16 gram of solid Sulphur is 3.011 × 10²³



★★ HOPE THAT HELPS ☺️ ★★

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 16g of solid sulpur contains

(6.022×10^23 /256 )16 molecules

= 3.76 × 10^22 molecules (approx)

____________________________

I hope, this will help you.☺

Thank you______❤

✿┅═══❁✿ Be Brainly✿❁═══┅✿