Question

Calculate no of water molecules present in 27g of water

Answer 1

No. Of moles = 27 / 18 = 3/2

So molecules will be 3/2 × Avogadro's number = 1.5 × 6.022 × 10 ^23

= 9.033 × 10 ^23 molecules

Hope it helps!

Answer 2

heya !!!!!! 18g of water contains 6.022×10^23molecules. 1g of water will contain 6.022×10^23/18molecules 27g of water will contain 27×6.022×10^23/18molecules====9.033×10^23 molecules hope it helps u mark as bra in lie st