Question

Calculate no.vof Oxygen atoms in 88g CO2 . Also calculate mass of CO having same no. of oxygen atoms​

Answer 1

Answer:

Explanation:

In 1 mole (44g) CO2 thr r 2N no. of oxygen atoms......therefore in 88g thr will be 4N oxygen atoms.

Where N is avogadro number = 6.023*10^23

Similarly,for CO (28g=1 mole),

28g---> N O atoms

x g---> 4N O atoms

Therefore 4*28=112g required.

Answer 2

Molecular weight of CO2CO2 =44 and it has 32g O2O2 and one molecule of O2O2 has 2 atoms.

44gCO244gCO2 has 2N2N atoms of O

88g88g CO2CO2 has 2N atoms =2×6.023×1023×88442×6.023×1023×8844

⇒24.092×1023⇒24.092×1023atoms of O2O2

CO=28

N atoms of O present in 28g CO

24.092×102324.092×1023 atoms of O=28×24.092×10236.023×102328×24.092×10236.023×1023

⇒112g⇒112g CO