Question

Calculate normality of 20 ml H2O2solution that reacts with 80 ml of 0.25 N KMnO4​

Answer 1

Answer:

2KMnO

4

(aq)+5H

2

O

2

(aq)+3H

2

SO

4

(aq)→K

2

SO

4

(aq)+2MnSO

4

(aq)+5O

2

(g)+8H

2

O(aq)

This is the balance chemical equation taking place :

This reaction suggests that for the for the same molarity ,suppose 0.05M , if KMnO4 has 80 mL , then H2O2 volume which will react completely is 5/2∗80=200mL .

As given is only 20 mL H

2

O

2

so 0.05 M (200 mL ) = actual molarity * 20 mL

actual molarty = 0.05∗200/20=0.50M.

As 1 M H

2

O

2

has 11.2 M volume strenth , then 0.5 will has 5.6 M, volume strength.

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Answer 2

Answer:

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5.6