Question

calculate normality of HCL solution if 50cc dissolve 0.1g NAOH​

Answer 1

Answer:

${Normality=0.04 \ N}$

Explanation:

Given :

Volume = 50 cc

Given mass = 0.1 g

We know formula for Normality ( N )

$\displaystyle{Normality=\dfrac{Numbers \ of \ equivalent}{Volume \ of \ solution(in \ mL)}\times1000 }$

First let's find Numbers of equivalent

$\displaystyle{Numbers \ of \ equivalent=n-factor\times mole}\\\\\displaystyle{n-factor \ of \ HCL=1}\\\\\displaystyle{No. \ of \ mole \ of \ HCL=\dfrac{0.1}{37.5}=0.002 \ moles}\\\\\displaystyle{Numbers \ of \ equivalent=1\times0.002=0.002}$

Now put the value in Normality equation we get

${Normality=\dfrac{Numbers \ of \ equivalent}{Volume \ of \ solution(in \ mL)}\times1000 }\\\\\\{Normality=\dfrac{0.002}{50}\times1000}\\\\\\{Normality=\dfrac{2}{50}\\\\\\{Normality=0.04 \ N}$

Thus we Normality = 0.04 N.