Question

Calculate normality of Na which contain 3g NaOH in 250 ml water​

Answer 1

Answer:

Hope it will help you

Explanation:

Molar mass of NaOH = 23+16+1 = 40g/mol

1mg = 1×10^-3g

250ml = 25×10¹×10^-3 L = 25×10^-2L

Molarity : the number of moles of solute present in a one liter volume of a solution .

Molarity = number of moles/volume of solution

Molarity = mass of solute/(molar mass of solute×volume of solution)

Molarity = 10^-3/(40×25×10^-2)

Molarity = 10^-3+2/1000

Molarity = 10^-1/10^3

Molarity = 10^-1–3

Molarity = 10^-4mol/L

Answer 2

Answer:

Normality( N) = gram equivalents/ volume in litres

Here, no of equivalents= weight/ gram eq. weight = 3/40 ( as n-factor of NaOH= 1)

Volume in litres= 1/4 litre

Therefore using the formula, N= 0.3N

[ NOTE: Please check a list of n-factors to help in normality related sums.]