Question

calculate normality solution obtained by mixing 10.6g of Na2CO3 in 100 ml water?

Answer 1

Hey mate!

Here's your answer

Normality (N) of solution is “ the number of gram equivalent weight of the solute present in per litre of it solution”.

Normality (N) =

Weight in grams of the solute per litre of solution ÷ Gram equivalent weight of the solute.

Molecular weight of Na2CO3 = 23*2+12+16*3

= 46+12 +48 = 106 gms

Equivalent weight of Na2CO3 = 106/2 = 53

For 100 ml Na2CO3 Contains 10.6 gm

For 1000 ml Na2CO3 contains =

1000*10.6/100 =10* 10.6 = 106.0 Gms

Normality = 106/ 53 =2N

Normality of the solution = 2N

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