Question

calculate number of atom present in 15 gram of sodium​

Answer 1

ans .is 3.9 ×10^23

explanation

23g of na has atoms = 6.022 ×10^23

1g has atoms =6.022×10^23/23

15 g has atoms = 6.022×10^23×15/23

= 3.9×10^23 atoms