calculate number of atoms in 120g of iron which one has more atoms and how much is difference?
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40 g of Ca = 1 mol
120 g = 120/40 = 3 mol
1 mol contains 6.022 x 10^23 atoms
Therefore,
3 mol contains 3 x 6.022 x 10^23 Ca atom
= 18.066 x 10^23 Ca atoms
56 g of Fe = 1 mol
120 g of Fe = 120/56 = 2.14 mol
1 mol contains 6.022 x 10^23 atoms
2.14 mol = 2.14 x 6.022 x 10^23 atoms
= 12.887 x 10^23 Fe atoms
Calcium has more no. of atoms.
Difference = 5.179 x 10^23 atoms
120 g = 120/40 = 3 mol
1 mol contains 6.022 x 10^23 atoms
Therefore,
3 mol contains 3 x 6.022 x 10^23 Ca atom
= 18.066 x 10^23 Ca atoms
56 g of Fe = 1 mol
120 g of Fe = 120/56 = 2.14 mol
1 mol contains 6.022 x 10^23 atoms
2.14 mol = 2.14 x 6.022 x 10^23 atoms
= 12.887 x 10^23 Fe atoms
Calcium has more no. of atoms.
Difference = 5.179 x 10^23 atoms
swapnilmessi10:
Thx bro
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