Question

Calculate number of atoms in 52g of Helium

Answer 1

The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. 

Hence 1 mole of He = 4 g of He = 6.022 X 1023atoms of  He

 1 g of He = (6.022 X 1023) / 4 atoms of  He

52 g of He = (6.022 X 1023X 52 ) / 4 atoms of  He

 = 7.829 X 1024 atoms of He

Answer 2

Answer:

$7.53*10^{23}$ Helium atoms are present.

Explanation:

• We know that 1 mole of helium atoms weighs 4g.
• 1 mole contains $6.02 * 10^{23}$ atoms, molecules, or ions.
• We can calculate the number of helium atoms in 52g by-

4g of helium = $6.02 * 10^{23}$ atoms of helium

52g of helium = $x$ atoms of helium

$52 * (6.02*10^{23})$ = $4 * x$

$3.01*10^{24}=4x$

$\frac{3.01*10^{24} }{4}=x$

$7.53 * 10^{23} = x$

Conclusion:

52g of Helium has $7.53*10^{23}$ atoms.