Question

calculate number of atoms of hydrogen present in 5.6 g of urea.

Answer 1

Answer:

2.24 × 10^23

Explanation:

Molecular formula of urea = CH4N2O

No of atoms of hydrogen present in urea = no of moles × Avogadro number × atomicity of hydrogen

no of moles = given mass ÷ molecular mass

i.e) = 5.6÷60 = 0.093

Therefore no of atoms of hydrogen = 0.093 × 6 × 10^23 × 4 ( since atomicity of hydrogen in urea is 4 )

Hence the answer is 2.24 × 10^23

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