Question

Calculate number of atoms of oxygen present in 3.42g of sucrose

Answer 1

Answer:

Av- 6.022 X 10²³

B.O - Bond oder

1 mol of O2 (oxygen ) - (2 X Av)

[1 mol of O2 = molar mass of O2 ]

there for 1 g of O2=(B.O X Av) /(molar mass of O2) so, 3.42g of O2 =3.42(2 X Av) /(molar mass of O2) = 1.28 X 10²³ atoms.

Hence, 3.42g of O2 have 1.28 X 10²³ atoms.