Question

calculate number of atoms of sodium present in 1.06 gm of Na2Co3.
plz send quickly​

Answer 1

Answer:

Correct option is

C

1.806×1023

1 mole of Na2CO3=106g

moles in 10.6g of Na2CO3=10.6/106=0.1 mole

106g contain atoms of oxygen =3×6.022×1023

10.6 contain atoms =0.1×3×6.022×1023

                                 =1.8×1023 atoms.